(ii) Perhaps you have used the proper quantity of high data? occurrence (step 1.03 ) possess step 3 extreme rates frequency (1) keeps step one tall figure When multiplying otherwise dividing, how many tall numbers about outcome is the same since the least number of extreme rates in the terminology used, so we was rationalized in making use of step one high shape. Our very own answer (ten30) possess 4 significant data! Since the audience is merely rationalized in using step 1 extreme figure, we could supply the respond to because one thousand grams, nevertheless the best answer will be to fool around with medical notation and develop step one ? ten 3 grams
(iii) Will be your address plausible? Manage an effective “rough” calculation: density ≈ step one g mL -1 step one mL out-of whole milk have quite a few from the step 1 g step 1 L (a thousand mL) away from milk possess scores of regarding the one thousand ? step one = a thousand g Because this harsh formula is virtually the fresh very carefully determined well worth to own mass we are fairly positive that our respond to is right.
Concern 5. In the twenty five°C and step one automatic teller machine tension, diamond possess an occurrence off step three.5 g cm -step 3 . Assess the amount inside cm step 3 of 0.50 grams regarding diamond at the twenty five°C and you will step 1 automatic teller machine stress.
step three.5 grams cm -step three ? V (cm step three ) = V(cm 3 ) ? 0.fifty g ? V (cm 3 ) step 3.5 g cm -step 3 ? V (cm step three ) = 0.50 grams
[ step 3.5 grams cm -3 ? V (cm step three )] ? step three.5 g cm -3 = 0.50 grams ? step 3.5 g cm -step 3 V (cm 3 ) = 0.fifty ? step three.5 (cm -3 ) = 0.fourteen cm 3
Carry out a great “rough” calculation: thickness ≈ 5 grams cm -step three step 1 cm -3 out of diamond possess a mass of from the 5 g
(ii) Maybe you’ve utilized the right quantity of tall rates? thickness (step 3.5) enjoys dos extreme figures frequency (0.50) have dos tall numbers When multiplying or separating, what number of tall figures regarding the result is the same since the very least number of significant data on words made use of, so we try justified in making use of 2 high data. Our very own answer (0.14) have dos extreme data
(iii) Is your answer plausible? 50 g for the mass which is 1 /10 th the mass of 1 cm -3 of diamond So the volume of 0.50 g of diamond will 1 /10 th the volume that is V = 1 /10 ? 1 cm 3 = 0.1 cm 3 Since this “rough” answer is about the same as our carefully calculated answer we are reasonably confident that our answer is correct.
Matter six. In the twenty-five°C and you may 1 atm pressure, ethylene glycol features a density of just one.11 g mL -1 . Determine the amount within the mL off 0.025 kilogram of ethylene glycol during the twenty five°C and New Mexico dating sites you may step one atm tension.
Transfer bulk in kilogram to help you mass during the grams to help you remain consistent with equipment out of density (g mL -1 ):
V (mL) ? step 1.eleven (g mL -step 1 ) = V (mL) ? twenty-five (g) ? V (mL) V (mL) ? step 1.11 (g mL -step 1 ) = twenty-five (g)
The question gives us 0
[V (mL) ? step 1.11 (g mL -1 ) ] ? step one.eleven (grams mL -step one ) = twenty five (g) ? 1.11 ( grams mL -step 1 ) V (mL) = twenty five ? step 1.11 (mL -1 ) = 23 mL
(ii) Maybe you have made use of the right level of tall figures? mass (0.025) has 2 significant figures occurrence (step 1.11) features step three extreme numbers Whenever multiplying otherwise splitting, what amount of extreme data regarding the outcome is an equivalent because the the very least number of high data on the terms and conditions made use of, so we is actually justified in making use of 2 extreme figures. All of our address (25) has actually 2 tall figures